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2x(x+3)=2x^2+6x
We move all terms to the left:
2x(x+3)-(2x^2+6x)=0
We multiply parentheses
2x^2+6x-(2x^2+6x)=0
We get rid of parentheses
2x^2-2x^2+6x-6x=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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