2x(x+3)=28

Solution for 2x(x+3)=28 equation:

2x(x+3)=28

We move all terms to the left:

2x(x+3)-(28)=0

We multiply parentheses

2x^2+6x-28=0

a = 2; b = 6; c = -28;
Δ = b2-4ac
Δ = 62-4·2·(-28)
Δ = 260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{260}=\sqrt{4*65}=\sqrt{4}*\sqrt{65}=2\sqrt{65}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{65}}{2*2}=\frac{-6-2\sqrt{65}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{65}}{2*2}=\frac{-6+2\sqrt{65}}{4}
$