2x(x+20)=16x-70

Solution for 2x(x+20)=16x-70 equation:

2x(x+20)=16x-70

We move all terms to the left:

2x(x+20)-(16x-70)=0

We multiply parentheses

2x^2+40x-(16x-70)=0

We get rid of parentheses

2x^2+40x-16x+70=0

We add all the numbers together, and all the variables

2x^2+24x+70=0

a = 2; b = 24; c = +70;
Δ = b2-4ac
Δ = 242-4·2·70
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4}{2*2}=\frac{-28}{4}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4}{2*2}=\frac{-20}{4}
=-5
$