2x(x+2)-3(x-1)=x(7+2x)

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Solution for 2x(x+2)-3(x-1)=x(7+2x) equation: 



2x(x+2)-3(x-1)=x(7+2x)

We move all terms to the left:

2x(x+2)-3(x-1)-(x(7+2x))=0

We add all the numbers together, and all the variables

2x(x+2)-3(x-1)-(x(2x+7))=0

We multiply parentheses

2x^2+4x-3x-(x(2x+7))+3=0



We calculate terms in parentheses: -(x(2x+7)), so:

x(2x+7)

We multiply parentheses

2x^2+7x

Back to the equation:

-(2x^2+7x)



We add all the numbers together, and all the variables

2x^2+x-(2x^2+7x)+3=0

We get rid of parentheses

2x^2-2x^2+x-7x+3=0

We add all the numbers together, and all the variables

-6x+3=0

We move all terms containing x to the left, all other terms to the right

-6x=-3

x=-3/-6

x=1/2

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