2x(x+10)=3(x-20)

Solution for 2x(x+10)=3(x-20) equation:

2x(x+10)=3(x-20)

We move all terms to the left:

2x(x+10)-(3(x-20))=0

We multiply parentheses

2x^2+20x-(3(x-20))=0


We calculate terms in parentheses: -(3(x-20)), so:

3(x-20)

We multiply parentheses

3x-60

Back to the equation:

-(3x-60)


We get rid of parentheses

2x^2+20x-3x+60=0

We add all the numbers together, and all the variables

2x^2+17x+60=0

a = 2; b = 17; c = +60;
Δ = b2-4ac
Δ = 172-4·2·60
Δ = -191
Delta is less than zero, so there is no solution for the equation