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2x(x+1)=2x^2-1/5
We move all terms to the left:
2x(x+1)-(2x^2-1/5)=0
We multiply parentheses
2x^2+2x-(2x^2-1/5)=0
We get rid of parentheses
2x^2-2x^2+2x+1/5=0
We multiply all the terms by the denominator
2x^2*5-2x^2*5+2x*5+1=0
Wy multiply elements
10x^2-10x^2+10x+1=0
We add all the numbers together, and all the variables
10x+1=0
We move all terms containing x to the left, all other terms to the right
10x=-1
x=-1/10
x=-1/10
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