2x(x)(x-3)=144

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Solution for 2x(x)(x-3)=144 equation:



2x(x)(x-3)=144
We move all terms to the left:
2x(x)(x-3)-(144)=0
We multiply parentheses
2x^2-6x-144=0
a = 2; b = -6; c = -144;
Δ = b2-4ac
Δ = -62-4·2·(-144)
Δ = 1188
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1188}=\sqrt{36*33}=\sqrt{36}*\sqrt{33}=6\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6\sqrt{33}}{2*2}=\frac{6-6\sqrt{33}}{4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6\sqrt{33}}{2*2}=\frac{6+6\sqrt{33}}{4} $

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