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2x(x-4)=-16
We move all terms to the left:
2x(x-4)-(-16)=0
We add all the numbers together, and all the variables
2x(x-4)+16=0
We multiply parentheses
2x^2-8x+16=0
a = 2; b = -8; c = +16;
Δ = b2-4ac
Δ = -82-4·2·16
Δ = -64
Delta is less than zero, so there is no solution for the equation
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