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2x(9+x)=72
We move all terms to the left:
2x(9+x)-(72)=0
We add all the numbers together, and all the variables
2x(x+9)-72=0
We multiply parentheses
2x^2+18x-72=0
a = 2; b = 18; c = -72;
Δ = b2-4ac
Δ = 182-4·2·(-72)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-30}{2*2}=\frac{-48}{4} =-12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+30}{2*2}=\frac{12}{4} =3 $
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