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2x(7x+6)+3x=63
We move all terms to the left:
2x(7x+6)+3x-(63)=0
We add all the numbers together, and all the variables
3x+2x(7x+6)-63=0
We multiply parentheses
14x^2+3x+12x-63=0
We add all the numbers together, and all the variables
14x^2+15x-63=0
a = 14; b = 15; c = -63;
Δ = b2-4ac
Δ = 152-4·14·(-63)
Δ = 3753
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3753}=\sqrt{9*417}=\sqrt{9}*\sqrt{417}=3\sqrt{417}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-3\sqrt{417}}{2*14}=\frac{-15-3\sqrt{417}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+3\sqrt{417}}{2*14}=\frac{-15+3\sqrt{417}}{28} $
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