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2x(6x-20)=180
We move all terms to the left:
2x(6x-20)-(180)=0
We multiply parentheses
12x^2-40x-180=0
a = 12; b = -40; c = -180;
Δ = b2-4ac
Δ = -402-4·12·(-180)
Δ = 10240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{10240}=\sqrt{1024*10}=\sqrt{1024}*\sqrt{10}=32\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-32\sqrt{10}}{2*12}=\frac{40-32\sqrt{10}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+32\sqrt{10}}{2*12}=\frac{40+32\sqrt{10}}{24} $
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