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2x(5x-3)=24
We move all terms to the left:
2x(5x-3)-(24)=0
We multiply parentheses
10x^2-6x-24=0
a = 10; b = -6; c = -24;
Δ = b2-4ac
Δ = -62-4·10·(-24)
Δ = 996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{996}=\sqrt{4*249}=\sqrt{4}*\sqrt{249}=2\sqrt{249}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{249}}{2*10}=\frac{6-2\sqrt{249}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{249}}{2*10}=\frac{6+2\sqrt{249}}{20} $
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