2x(5x-2)=20

Solution for 2x(5x-2)=20 equation:

2x(5x-2)=20

We move all terms to the left:

2x(5x-2)-(20)=0

We multiply parentheses

10x^2-4x-20=0

a = 10; b = -4; c = -20;
Δ = b2-4ac
Δ = -42-4·10·(-20)
Δ = 816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{816}=\sqrt{16*51}=\sqrt{16}*\sqrt{51}=4\sqrt{51}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{51}}{2*10}=\frac{4-4\sqrt{51}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{51}}{2*10}=\frac{4+4\sqrt{51}}{20}
$