2x(4x+8)+2x(4x+8)=88

Solution for 2x(4x+8)+2x(4x+8)=88 equation:

2x(4x+8)+2x(4x+8)=88

We move all terms to the left:

2x(4x+8)+2x(4x+8)-(88)=0

We multiply parentheses

8x^2+8x^2+16x+16x-88=0

We add all the numbers together, and all the variables

16x^2+32x-88=0

a = 16; b = 32; c = -88;
Δ = b2-4ac
Δ = 322-4·16·(-88)
Δ = 6656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6656}=\sqrt{256*26}=\sqrt{256}*\sqrt{26}=16\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-16\sqrt{26}}{2*16}=\frac{-32-16\sqrt{26}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+16\sqrt{26}}{2*16}=\frac{-32+16\sqrt{26}}{32}
$