2x(4x+48)=180

Solution for 2x(4x+48)=180 equation:

2x(4x+48)=180

We move all terms to the left:

2x(4x+48)-(180)=0

We multiply parentheses

8x^2+96x-180=0

a = 8; b = 96; c = -180;
Δ = b2-4ac
Δ = 962-4·8·(-180)
Δ = 14976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14976}=\sqrt{576*26}=\sqrt{576}*\sqrt{26}=24\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-24\sqrt{26}}{2*8}=\frac{-96-24\sqrt{26}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+24\sqrt{26}}{2*8}=\frac{-96+24\sqrt{26}}{16}
$