2x(3x-5)=6x2+x33

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Solution for 2x(3x-5)=6x2+x33 equation: 



2x(3x-5)=6x^2+x33

We move all terms to the left:

2x(3x-5)-(6x^2+x33)=0

We multiply parentheses

6x^2-10x-(6x^2+x33)=0

We get rid of parentheses

6x^2-6x^2-10x-x33=0

We add all the numbers together, and all the variables

-1x^33-10x=0

We do not support expression: x^33

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