2x(3x-4)=2x-8

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Solution for 2x(3x-4)=2x-8 equation: 



2x(3x-4)=2x-8

We move all terms to the left:

2x(3x-4)-(2x-8)=0

We multiply parentheses

6x^2-8x-(2x-8)=0

We get rid of parentheses

6x^2-8x-2x+8=0

We add all the numbers together, and all the variables

6x^2-10x+8=0

a = 6; b = -10; c = +8;
Δ = b2-4ac
Δ = -102-4·6·8
Δ = -92
Delta is less than zero, so there is no solution for the equation

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