2x(3x-26)=180

Solution for 2x(3x-26)=180 equation:

2x(3x-26)=180

We move all terms to the left:

2x(3x-26)-(180)=0

We multiply parentheses

6x^2-52x-180=0

a = 6; b = -52; c = -180;
Δ = b2-4ac
Δ = -522-4·6·(-180)
Δ = 7024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7024}=\sqrt{16*439}=\sqrt{16}*\sqrt{439}=4\sqrt{439}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-4\sqrt{439}}{2*6}=\frac{52-4\sqrt{439}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+4\sqrt{439}}{2*6}=\frac{52+4\sqrt{439}}{12}
$