2x(3x-10)=2x2-25

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Solution for 2x(3x-10)=2x2-25 equation: 



2x(3x-10)=2x^2-25

We move all terms to the left:

2x(3x-10)-(2x^2-25)=0

We multiply parentheses

6x^2-20x-(2x^2-25)=0

We get rid of parentheses

6x^2-2x^2-20x+25=0

We add all the numbers together, and all the variables

4x^2-20x+25=0

a = 4; b = -20; c = +25;
Δ = b2-4ac
Δ = -202-4·4·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{20}{8}=2+1/2$

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