2x(3x-1)=98

Solution for 2x(3x-1)=98 equation:

2x(3x-1)=98

We move all terms to the left:

2x(3x-1)-(98)=0

We multiply parentheses

6x^2-2x-98=0

a = 6; b = -2; c = -98;
Δ = b2-4ac
Δ = -22-4·6·(-98)
Δ = 2356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2356}=\sqrt{4*589}=\sqrt{4}*\sqrt{589}=2\sqrt{589}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{589}}{2*6}=\frac{2-2\sqrt{589}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{589}}{2*6}=\frac{2+2\sqrt{589}}{12}
$