2x(3x-1)=6x2-5

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Solution for 2x(3x-1)=6x2-5 equation:



2x(3x-1)=6x^2-5
We move all terms to the left:
2x(3x-1)-(6x^2-5)=0
We multiply parentheses
6x^2-2x-(6x^2-5)=0
We get rid of parentheses
6x^2-6x^2-2x+5=0
We add all the numbers together, and all the variables
-2x+5=0
We move all terms containing x to the left, all other terms to the right
-2x=-5
x=-5/-2
x=2+1/2

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