2x(3x-1)=2x

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Solution for 2x(3x-1)=2x equation:



2x(3x-1)=2x
We move all terms to the left:
2x(3x-1)-(2x)=0
We add all the numbers together, and all the variables
-2x+2x(3x-1)=0
We multiply parentheses
6x^2-2x-2x=0
We add all the numbers together, and all the variables
6x^2-4x=0
a = 6; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·6·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*6}=\frac{0}{12} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*6}=\frac{8}{12} =2/3 $

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