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2x(2x-2.5)=5(x-25)
We move all terms to the left:
2x(2x-2.5)-(5(x-25))=0
We multiply parentheses
4x^2-5x-(5(x-25))=0
We calculate terms in parentheses: -(5(x-25)), so:We get rid of parentheses
5(x-25)
We multiply parentheses
5x-125
Back to the equation:
-(5x-125)
4x^2-5x-5x+125=0
We add all the numbers together, and all the variables
4x^2-10x+125=0
a = 4; b = -10; c = +125;
Δ = b2-4ac
Δ = -102-4·4·125
Δ = -1900
Delta is less than zero, so there is no solution for the equation
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