2x(2x+32)=x+28

Solution for 2x(2x+32)=x+28 equation:

2x(2x+32)=x+28

We move all terms to the left:

2x(2x+32)-(x+28)=0

We multiply parentheses

4x^2+64x-(x+28)=0

We get rid of parentheses

4x^2+64x-x-28=0

We add all the numbers together, and all the variables

4x^2+63x-28=0

a = 4; b = 63; c = -28;
Δ = b2-4ac
Δ = 632-4·4·(-28)
Δ = 4417
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-\sqrt{4417}}{2*4}=\frac{-63-\sqrt{4417}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+\sqrt{4417}}{2*4}=\frac{-63+\sqrt{4417}}{8}
$