2x(1X+10)=27

Solution for 2x(1X+10)=27 equation:

2x(1x+10)=27

We move all terms to the left:

2x(1x+10)-(27)=0

We add all the numbers together, and all the variables

2x(x+10)-27=0

We multiply parentheses

2x^2+20x-27=0

a = 2; b = 20; c = -27;
Δ = b2-4ac
Δ = 202-4·2·(-27)
Δ = 616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{616}=\sqrt{4*154}=\sqrt{4}*\sqrt{154}=2\sqrt{154}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-2\sqrt{154}}{2*2}=\frac{-20-2\sqrt{154}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+2\sqrt{154}}{2*2}=\frac{-20+2\sqrt{154}}{4}
$