2x(10-x)=50

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Solution for 2x(10-x)=50 equation: 



2x(10-x)=50

We move all terms to the left:

2x(10-x)-(50)=0

We add all the numbers together, and all the variables

2x(-1x+10)-50=0

We multiply parentheses

-2x^2+20x-50=0

a = -2; b = 20; c = -50;
Δ = b2-4ac
Δ = 202-4·(-2)·(-50)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-20}{-4}=+5$

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