2x(1-x)=3(2x+6)

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Solution for 2x(1-x)=3(2x+6) equation: 



2x(1-x)=3(2x+6)

We move all terms to the left:

2x(1-x)-(3(2x+6))=0

We add all the numbers together, and all the variables

2x(-1x+1)-(3(2x+6))=0

We multiply parentheses

-2x^2+2x-(3(2x+6))=0



We calculate terms in parentheses: -(3(2x+6)), so:

3(2x+6)

We multiply parentheses

6x+18

Back to the equation:

-(6x+18)



We get rid of parentheses

-2x^2+2x-6x-18=0

We add all the numbers together, and all the variables

-2x^2-4x-18=0

a = -2; b = -4; c = -18;
Δ = b2-4ac
Δ = -42-4·(-2)·(-18)
Δ = -128
Delta is less than zero, so there is no solution for the equation

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