2x(-6+x)=90

Solution for 2x(-6+x)=90 equation:

2x(-6+x)=90

We move all terms to the left:

2x(-6+x)-(90)=0

We add all the numbers together, and all the variables

2x(x-6)-90=0

We multiply parentheses

2x^2-12x-90=0

a = 2; b = -12; c = -90;
Δ = b2-4ac
Δ = -122-4·2·(-90)
Δ = 864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{864}=\sqrt{144*6}=\sqrt{144}*\sqrt{6}=12\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12\sqrt{6}}{2*2}=\frac{12-12\sqrt{6}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12\sqrt{6}}{2*2}=\frac{12+12\sqrt{6}}{4}
$