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2x(-3x-7)=0
We multiply parentheses
-6x^2-14x=0
a = -6; b = -14; c = 0;
Δ = b2-4ac
Δ = -142-4·(-6)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-14}{2*-6}=\frac{0}{-12} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+14}{2*-6}=\frac{28}{-12} =-2+1/3 $
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