2x^2-8y^2=0

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Solution for 2x^2-8y^2=0 equation: 


Simplifying
2x2 + -8y2 = 0

Solving
2x2 + -8y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8y2' to each side of the equation.
2x2 + -8y2 + 8y2 = 0 + 8y2

Combine like terms: -8y2 + 8y2 = 0
2x2 + 0 = 0 + 8y2
2x2 = 0 + 8y2
Remove the zero:
2x2 = 8y2

Divide each side by '2'.
x2 = 4y2

Simplifying
x2 = 4y2

Take the square root of each side:
x = {-2y, 2y}

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