If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2-7x-63=0
a = 2; b = -7; c = -63;
Δ = b2-4ac
Δ = -72-4·2·(-63)
Δ = 553
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{553}}{2*2}=\frac{7-\sqrt{553}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{553}}{2*2}=\frac{7+\sqrt{553}}{4} $
| m+2=m−215 | | 10p-3=(12+4p)=7 | | 5/x-7=-4 | | 1.3=r/7+0.3 | | 7(x-3)=x+21 | | 9x+6=-3x-30 | | -20y+15=2-6y+11 | | -17+1=-4(x+2) | | 8x/85=87 | | 12u+12=132 | | 2(x+4.2)=16.2* | | 12=x/4+5 | | 6b-9=9 | | m/3+6=-2 | | 10(a-5)=6(a-3 | | 5(x+2)=2x+7 | | 5s-3=43 | | -14=-6+-4x | | 9+12=-3(3x-7) | | -20-x/4=22 | | 6+2(x-4)=2((x-1) | | 12=1x-0.3x+18 | | 2+x+2x+4=16+10 | | V=1/3x3.14x12^2x19 | | -9x-14=16-4x | | 17-5x=77 | | 2/5(-5+10y)=14 | | 2x+27=5x+36 | | -4m+3(-3m-2)=59 | | -7x-12=58 | | 15-x=-19 | | y=0.1(1+0.23) |