2w2+3w+12=5

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Solution for 2w2+3w+12=5 equation:



2w^2+3w+12=5
We move all terms to the left:
2w^2+3w+12-(5)=0
We add all the numbers together, and all the variables
2w^2+3w+7=0
a = 2; b = 3; c = +7;
Δ = b2-4ac
Δ = 32-4·2·7
Δ = -47
Delta is less than zero, so there is no solution for the equation

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