2w(4w+3)=3w

Solution for 2w(4w+3)=3w equation:

2w(4w+3)=3w

We move all terms to the left:

2w(4w+3)-(3w)=0

We add all the numbers together, and all the variables

-3w+2w(4w+3)=0

We multiply parentheses

8w^2-3w+6w=0

We add all the numbers together, and all the variables

8w^2+3w=0

a = 8; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·8·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*8}=\frac{-6}{16}
=-3/8
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*8}=\frac{0}{16}
=0
$