2v-8+2(4v+2)=-2(v+9)

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Solution for 2v-8+2(4v+2)=-2(v+9) equation:



2v-8+2(4v+2)=-2(v+9)
We move all terms to the left:
2v-8+2(4v+2)-(-2(v+9))=0
We multiply parentheses
2v+8v-(-2(v+9))+4-8=0
We calculate terms in parentheses: -(-2(v+9)), so:
-2(v+9)
We multiply parentheses
-2v-18
Back to the equation:
-(-2v-18)
We add all the numbers together, and all the variables
10v-(-2v-18)-4=0
We get rid of parentheses
10v+2v+18-4=0
We add all the numbers together, and all the variables
12v+14=0
We move all terms containing v to the left, all other terms to the right
12v=-14
v=-14/12
v=-1+1/6

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