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2v-7+4(2v+2)=-5(v+1)
We move all terms to the left:
2v-7+4(2v+2)-(-5(v+1))=0
We multiply parentheses
2v+8v-(-5(v+1))+8-7=0
We calculate terms in parentheses: -(-5(v+1)), so:We add all the numbers together, and all the variables
-5(v+1)
We multiply parentheses
-5v-5
Back to the equation:
-(-5v-5)
10v-(-5v-5)+1=0
We get rid of parentheses
10v+5v+5+1=0
We add all the numbers together, and all the variables
15v+6=0
We move all terms containing v to the left, all other terms to the right
15v=-6
v=-6/15
v=-2/5
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