2v-4+2(2v+3)=-4(v+1)

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Solution for 2v-4+2(2v+3)=-4(v+1) equation:



2v-4+2(2v+3)=-4(v+1)
We move all terms to the left:
2v-4+2(2v+3)-(-4(v+1))=0
We multiply parentheses
2v+4v-(-4(v+1))+6-4=0
We calculate terms in parentheses: -(-4(v+1)), so:
-4(v+1)
We multiply parentheses
-4v-4
Back to the equation:
-(-4v-4)
We add all the numbers together, and all the variables
6v-(-4v-4)+2=0
We get rid of parentheses
6v+4v+4+2=0
We add all the numbers together, and all the variables
10v+6=0
We move all terms containing v to the left, all other terms to the right
10v=-6
v=-6/10
v=-3/5

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