2v+5-2(-5v-2)=3(v-1)

Solution for 2v+5-2(-5v-2)=3(v-1) equation:

2v+5-2(-5v-2)=3(v-1)

We move all terms to the left:

2v+5-2(-5v-2)-(3(v-1))=0

We multiply parentheses

2v+10v-(3(v-1))+4+5=0


We calculate terms in parentheses: -(3(v-1)), so:

3(v-1)

We multiply parentheses

3v-3

Back to the equation:

-(3v-3)


We add all the numbers together, and all the variables

12v-(3v-3)+9=0

We get rid of parentheses

12v-3v+3+9=0

We add all the numbers together, and all the variables

9v+12=0

We move all terms containing v to the left, all other terms to the right

9v=-12

v=-12/9

v=-1+1/3