2v+28=4(v+6)

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Solution for 2v+28=4(v+6) equation: 



2v+28=4(v+6)

We move all terms to the left:

2v+28-(4(v+6))=0



We calculate terms in parentheses: -(4(v+6)), so:

4(v+6)

We multiply parentheses

4v+24

Back to the equation:

-(4v+24)



We get rid of parentheses

2v-4v-24+28=0

We add all the numbers together, and all the variables

-2v+4=0

We move all terms containing v to the left, all other terms to the right

-2v=-4

v=-4/-2

v=+2

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