2v+2(1+4v)=62

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Solution for 2v+2(1+4v)=62 equation: 



2v+2(1+4v)=62

We move all terms to the left:

2v+2(1+4v)-(62)=0

We add all the numbers together, and all the variables

2v+2(4v+1)-62=0

We multiply parentheses

2v+8v+2-62=0

We add all the numbers together, and all the variables

10v-60=0

We move all terms containing v to the left, all other terms to the right

10v=60

v=60/10

v=6

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