2u-8+2(3u+6)=-2(u+6)

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Solution for 2u-8+2(3u+6)=-2(u+6) equation: 



2u-8+2(3u+6)=-2(u+6)

We move all terms to the left:

2u-8+2(3u+6)-(-2(u+6))=0

We multiply parentheses

2u+6u-(-2(u+6))+12-8=0



We calculate terms in parentheses: -(-2(u+6)), so:

-2(u+6)

We multiply parentheses

-2u-12

Back to the equation:

-(-2u-12)



We add all the numbers together, and all the variables

8u-(-2u-12)+4=0

We get rid of parentheses

8u+2u+12+4=0

We add all the numbers together, and all the variables

10u+16=0

We move all terms containing u to the left, all other terms to the right

10u=-16

u=-16/10

u=-1+3/5

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