2u-4+2(6u+3)=-2(u+8)

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Solution for 2u-4+2(6u+3)=-2(u+8) equation: 



2u-4+2(6u+3)=-2(u+8)

We move all terms to the left:

2u-4+2(6u+3)-(-2(u+8))=0

We multiply parentheses

2u+12u-(-2(u+8))+6-4=0



We calculate terms in parentheses: -(-2(u+8)), so:

-2(u+8)

We multiply parentheses

-2u-16

Back to the equation:

-(-2u-16)



We add all the numbers together, and all the variables

14u-(-2u-16)+2=0

We get rid of parentheses

14u+2u+16+2=0

We add all the numbers together, and all the variables

16u+18=0

We move all terms containing u to the left, all other terms to the right

16u=-18

u=-18/16

u=-1+1/8

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