2u-32=6(u-6)

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Solution for 2u-32=6(u-6) equation: 



2u-32=6(u-6)

We move all terms to the left:

2u-32-(6(u-6))=0



We calculate terms in parentheses: -(6(u-6)), so:

6(u-6)

We multiply parentheses

6u-36

Back to the equation:

-(6u-36)



We get rid of parentheses

2u-6u+36-32=0

We add all the numbers together, and all the variables

-4u+4=0

We move all terms containing u to the left, all other terms to the right

-4u=-4

u=-4/-4

u=1

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