2u+4(u-5)=16

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Solution for 2u+4(u-5)=16 equation: 



2u+4(u-5)=16

We move all terms to the left:

2u+4(u-5)-(16)=0

We multiply parentheses

2u+4u-20-16=0

We add all the numbers together, and all the variables

6u-36=0

We move all terms containing u to the left, all other terms to the right

6u=36

u=36/6

u=6

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