2u+2-2(-4u-5)=4(u-1)

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Solution for 2u+2-2(-4u-5)=4(u-1) equation: 



2u+2-2(-4u-5)=4(u-1)

We move all terms to the left:

2u+2-2(-4u-5)-(4(u-1))=0

We multiply parentheses

2u+8u-(4(u-1))+10+2=0



We calculate terms in parentheses: -(4(u-1)), so:

4(u-1)

We multiply parentheses

4u-4

Back to the equation:

-(4u-4)



We add all the numbers together, and all the variables

10u-(4u-4)+12=0

We get rid of parentheses

10u-4u+4+12=0

We add all the numbers together, and all the variables

6u+16=0

We move all terms containing u to the left, all other terms to the right

6u=-16

u=-16/6

u=-2+2/3

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