2u*2+7u+42=(u+6)*2

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Solution for 2u*2+7u+42=(u+6)*2 equation: 



2u*2+7u+42=(u+6)*2

We move all terms to the left:

2u*2+7u+42-((u+6)*2)=0

We add all the numbers together, and all the variables

7u+2u*2-((u+6)*2)+42=0

Wy multiply elements

7u+4u-((u+6)*2)+42=0



We calculate terms in parentheses: -((u+6)*2), so:

(u+6)*2

We multiply parentheses

2u+12

Back to the equation:

-(2u+12)



We add all the numbers together, and all the variables

11u-(2u+12)+42=0

We get rid of parentheses

11u-2u-12+42=0

We add all the numbers together, and all the variables

9u+30=0

We move all terms containing u to the left, all other terms to the right

9u=-30

u=-30/9

u=-3+1/3

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