2t2+t+28=0

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Solution for 2t2+t+28=0 equation: 



2t^2+t+28=0

a = 2; b = 1; c = +28;
Δ = b2-4ac
Δ = 12-4·2·28
Δ = -223
Delta is less than zero, so there is no solution for the equation

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