2t/3-6/t=t/2

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Solution for 2t/3-6/t=t/2 equation: 


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

(2*t)/3-(6/t) = t/2 // - t/2

(2*t)/3-(t/2)-(6/t) = 0

(2*t)/3-(t/2)-6*t^-1 = 0

1/6*t^1-6*t^-1 = 0

(1/6*t^2-6*t^0)/(t^1) = 0 // * t^2

t^1*(1/6*t^2-6*t^0) = 0

t^1

(1/6)*t^2-6 = 0

(1/6)*t^2-6 = 0

DELTA = 0^2-(-6*4*(1/6))

DELTA = 4

DELTA > 0

t = (4^(1/2)+0)/(2*(1/6)) or t = (0-4^(1/2))/(2*(1/6))

t = 6 or t = -6

t in { -6, 6} 

t in { -6, 6 }

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