2t-7/t=5

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Solution for 2t-7/t=5 equation: 


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

2*t-(7/t) = 5 // - 5

2*t-(7/t)-5 = 0

2*t-7*t^-1-5 = 0

2*t^1-7*t^-1-5*t^0 = 0

(2*t^2-5*t^1-7*t^0)/(t^1) = 0 // * t^2

t^1*(2*t^2-5*t^1-7*t^0) = 0

t^1

2*t^2-5*t-7 = 0

2*t^2-5*t-7 = 0

DELTA = (-5)^2-(-7*2*4)

DELTA = 81

DELTA > 0

t = (81^(1/2)+5)/(2*2) or t = (5-81^(1/2))/(2*2)

t = 7/2 or t = -1

t in { -1, 7/2} 

t in { -1, 7/2 }

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