2t-6+3t=2(-2t-2)+8

Solution for 2t-6+3t=2(-2t-2)+8 equation:

2t-6+3t=2(-2t-2)+8

We move all terms to the left:

2t-6+3t-(2(-2t-2)+8)=0

We add all the numbers together, and all the variables

5t-(2(-2t-2)+8)-6=0


We calculate terms in parentheses: -(2(-2t-2)+8), so:

2(-2t-2)+8

We multiply parentheses

-4t-4+8

We add all the numbers together, and all the variables

-4t+4

Back to the equation:

-(-4t+4)


We get rid of parentheses

5t+4t-4-6=0

We add all the numbers together, and all the variables

9t-10=0

We move all terms containing t to the left, all other terms to the right

9t=10

t=10/9

t=1+1/9