2t-6(2t-2(t+3)+5=8+5t-4t

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Solution for 2t-6(2t-2(t+3)+5=8+5t-4t equation: 



2t-6(2t-2(t+3)+5=8+5t-4t

We move all terms to the left:

2t-6(2t-2(t+3)+5-(8+5t-4t)=0

We add all the numbers together, and all the variables

2t-6(2t-2(t+3)+5-(t+8)=0

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